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How do you solve $cosx+sinxtanx=2$ ?

1 Answer

May 25, 2015

$tan(x) = sin(x)/cos(x)$

So
$cos(x) + sin(x)tan(x) = 2$

$rarr cos(x) + sin^2(x)/cos(x) = 2$

$rarr (cos^2(x) + sin^2(x))/cos(x) = 2$

$rarr 1/cos(x) = 2$

$rarr cos(x) = 1/2$

Based on one of the standard trigonometric triangles
$x = +-60^@$

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