How do you solve and write the following in interval notation: #-7x-2< -8x-6#?

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Answer 1 · 2017-04-27T04:35:16

#(-oo, -4)#

Given: #-7x-2 < -8x - 6#

Add #8x# to both sides of the inequality:

#-7x-2 + 8x < cancel(-8x) - 6 + cancel(8x)#

Simplify:

#x - 2 < -6#

Add #2@ to both sides of the inequality:

#x - 2 + 2 < -6 + 2#

Simplify:

#x < -4#

Interval notation: #(-oo, -4)#