How do you solve and write the following in interval notation: $3 x + 3 > 21$ $3x+3>21$ ?

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How do you solve and write the following in interval notation: $3 x + 3 > 21$ $3x+3>21$ ?

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Answer 1 · 2017-06-17T19:15:51

$(6, + \infty)$ $(6,+oo)$

Explanation:

$isolate 3x by subtracting 3 from both sides$ $"isolate 3x by subtracting 3 from both sides"$

$3xcancel(+3)cancel(-3)>21-3$

$rArr3x>18$

$"divide both sides by 3"$

$(cancel(3) x)/cancel(3)>18/3$

$rArrx>6" is the solution"$

$"in interval notation " (6,+oo)$

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How do you solve and write the following in interval notation: $3 x + 3 > 21$ $3x+3>21$ ?

1 Answer

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How do you solve and write the following in interval notation: $3 x + 3 > 21$ $3x+3>21$ ?