How do you solve and write the following in interval notation: #-19<10-x<=-11#?

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How do you solve and write the following in interval notation: #-19<10-x<=-11#?

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Answer 1 · 2016-06-14T09:36:03

#21<=x<29.#
Interval Form : #x in [21,29).#

Explanation:

Given that, #-19<10-x<=-11.#
We add -10 in the inequality (ineql.) to get, #-29<-x<=-21.#
Then, we multiply this ineql. by #-1#, a negative number, causing reversal of the order, #29>+x>=21,#,i.e., #21<=x<29.#

We can write this in Interval Form as #x in [21,29).#

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How do you solve and write the following in interval notation: #-19<10-x<=-11#?

1 Answer

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