# How do you solve and graph 5x+7<=32?

May 11, 2017

$x \le 5$

#### Explanation:

First we have
$5 x + 7 \le 32$
So we subtract 7 from both sides,
$5 x \le 25$
And then we divide both sides by 5,
$x \le 5$

To graph this on a TI calculator,

Press [y=]
Press [$x , T , \theta , n$]
Now press [2nd] and then press [math]
Select the inequality you want, in this case the $\le$
Press enter
Then you type 5

Finally press graph!

So you will see a straight line at $y = 1$ from $- \infty <$$x \le 5$ and $y = 0$ from $5 <$$x < \infty$.
The 1 indicates that the inequality is true and 0 indicates that the inequality is false. Just like how in computer language 1 is true and 0 is false.

Hope this helps :3