First, subtract #color(red)(15)# and add #color(blue)(2k)# to each side of the inequality to isolate the #k# term while keeping the inequality balanced:
#color(blue)(2k) + 4k + 15 - color(red)(15) > color(blue)(2k) - 2k + 3 - color(red)(15)#
#(color(blue)(2) + 4)k + 0 > 0 - 12#
#6k > -12#
Now, divide each side of the inequality by #color(red)(6)# to solve for #k# while keeping the inequality balanced:
#(6k)/color(red)(6) > -12/color(red)(6)#
#(color(red)(cancel(color(black)(6)))k)/cancel(color(red)(6)) > -2#
#k > -2#
