How do you solve and graph #2(n-4)<=6#?

1 Answer
Oct 5, 2016

#n\leq7#

Explanation:

You simply need to:

  • Expand the left hand side, to get #2n-8\leq 6#
  • Add #8# to both sides: #2n-8+8 \leq 6+8#, which leads to #2n \leq 14#
  • Divide both sides by #2#, to have #n \leq 7#

Since this is a one dimensional problem, you can graph it by drawing a number line, and considering all the numbers before #7# on that line