How do you solve and graph # 12 + x ≤ 9#?

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Answer 1 · 2017-08-12T13:31:28

See a solution process below:

Subtract #color(red)(12)# from each side of the inequality to solve for #x# while keeping the equation balanced:

#-color(red)(12) + 12 + x <= -color(red)(12) + 9#

#0 + x <= -3#

#x <= -3#

To graph we draw a solid, vertical line at the point #-3# on the #x-axis# and shade to the left of the line.

We use a solid line because the inequality contains "or equal to". If the inequality was just "less than" we would use a dashed line.

We shade to the left of the line because the inequality is a "less" inequality.

graph{x <= - 3}