# How do you solve and graph  12 + x ≤ 9?

Aug 12, 2017

See a solution process below:

#### Explanation:

Subtract $\textcolor{red}{12}$ from each side of the inequality to solve for $x$ while keeping the equation balanced:

$- \textcolor{red}{12} + 12 + x \le - \textcolor{red}{12} + 9$

$0 + x \le - 3$

$x \le - 3$

To graph we draw a solid, vertical line at the point $- 3$ on the $x - a \xi s$ and shade to the left of the line.

We use a solid line because the inequality contains "or equal to". If the inequality was just "less than" we would use a dashed line.

We shade to the left of the line because the inequality is a "less" inequality.

graph{x <= - 3}