How do you solve $9 v^{2} = - 45$ $9v^2=-45$ ?

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Answer 1 · 2017-08-20T21:20:28

Divide by 9 and take the square root of the answer.

$\frac{9 v^{2}}{9} = - \frac{45}{9}$ $(9v^2)/9 = -45/ 9" "$ This gives

$v^{2} = - 5$ $v^2 = - 5$

$v = \sqrt{- 5}$ $v = sqrt (-5)$

This is an imaginary number.

How do you solve 9v2=−459v^2=-45?