How do you solve #9tan^2x-3=0#?

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How do you solve #9tan^2x-3=0#?

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Answer 1 · 2017-02-07T16:19:25

#x in {pi/6+kpi,(5pi)/6+kpi}, AAkinZZ#

Explanation:

#9tan^2(x)-3=0#

#rarr 9tan^2(x)=3#

#rarr tan^2(x)=1/3#

#rarr tan(x)=+-1/sqrt(3)#

This is one of the standard reference angles: #pi/6 or 30^@#

Note the image below is (obviously) inaccurate.
Furthermore, I've used the #30^@# notation instead of #pi/6# because it was easier and faster to enter using my Paint program
enter image source here

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How do you solve #9tan^2x-3=0#?

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