How do you solve $9n^2+10=91$ ?

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Answer 1 · 2017-02-06T21:35:20

$n=+-3$

$9n^2+10=91$

$rarr 9n^2=81$ (after subtracting $10$ from each side)

$rarr n^2 =9$ (after dividing both sides by $9$ )

$rarr n=+-3$ (the two possible values which squared are equal to $9$ )

How do you solve 9n^2+10=919n^2+10=91?