# How do you solve 9^(5k)+8=50?

Oct 11, 2016

$k = 0.3402$

#### Explanation:

As ${9}^{5 k} + 8 = 50$,

${9}^{5 k} = 50 - 8 = 42$

or taking logarithm to base $10$, we get

$5 k \log 9 = \log 42$

or $k = \log \frac{42}{5 \log 9}$

or $k = \frac{1.62325}{5 \times 0.95424}$

or $k = 0.3402$