How do you solve $8 v^{2} - 12 = 308$ $8v^2-12=308$ ?

Question

1553 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-16T07:09:01

$v = \pm \sqrt{40}$ $v = +-sqrt40$

Usually a quadratic equation is solved by making it equal to 0.

However, this is a special case because there is no $x$ $x$ -term.
We can solve it by finding the square root.

$8 v^{2} - 12 = 308$ $8v^2 -12 = 308$

$8 v^{2} = 320 \leftarrow$ $8v^2 = 320" "larr$ add 12 to both sides

$v^{2} = 40 \leftarrow \div 8$ $v^2 = 40" "larr div 8$ on both sides

$v = \pm \sqrt{40}$ $v = +-sqrt40$

How do you solve 8v2−12=3088v^2-12=308?