How do you solve $8v^2-12=308$ ?

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Answer 1 · 2016-10-16T07:09:01

$v = +-sqrt40$

Usually a quadratic equation is solved by making it equal to 0.

However, this is a special case because there is no $x$ -term.
We can solve it by finding the square root.

$8v^2 -12 = 308$

$8v^2 = 320" "larr$ add 12 to both sides

$v^2 = 40" "larr div 8$ on both sides

$v = +-sqrt40$

How do you solve 8v^2-12=3088v^2-12=308?