# How do you solve -8e^(-p)=-49?

Jun 20, 2018

$p = \log \left(\frac{8}{49}\right)$

#### Explanation:

Divide both sides by $- 8$:

${e}^{- p} = \frac{49}{8}$

consider logarithm of both sides:

$\log \left({e}^{- p}\right) = \log \left(\frac{49}{8}\right)$

since $\log \left({e}^{s}\right) = s$, we have

$- p = \log \left(\frac{49}{8}\right)$

and thus

$p = - \log \left(\frac{49}{8}\right) = \log \left(\frac{8}{49}\right)$