How do you solve #7+t<=2(t+3)+2#?

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Answer 1 · 2017-05-04T16:01:51

#t>=-1#

One the whole, treat in the same way you do a normal equation. There are exceptions!

Given: #" "7+t<=2(t+3)+2#

subtract 2 from both sides

#5+t<=2(t+3)#

Multiply out the brackets

#5+t<=2t+6#

Subtract 6 from both sides

#-1+t<=2t#

Subtract #t# from both sides

#-1<=t#

#t>=-1" "larr# Notice that the open bit of #>=# has followed the #t#