# How do you solve -6x + 3< -18?

Jul 14, 2015

$x > \frac{7}{2}$

#### Explanation:

$- 6 x + 3 < - 18$

Solve for $x$ as if the expression is an equality.

Subtract $3$ from both sides.

$- 6 x < - 18 - 3$ =

$- 6 x < - 21$

Divide both sides by $- 6$. This will reverse the inequality.

$x > \frac{- 21}{- 6}$ =

$x > \frac{21}{6}$

Factor $\frac{21}{6}$.

$x > \frac{3 \cdot 7}{3 \cdot 2}$

Cancel $3$.

$x > \frac{\cancel{3} \cdot 7}{\cancel{3} \cdot 2}$

$x > \frac{7}{2}$