# How do you solve -6(x-4)>2x+8?

May 15, 2018

$x < 2$

#### Explanation:

Simply the equation further by opening the brackets first.

$- 6 \left(x - 4\right) > 2 x + 8$

$- 6 x - \left(4 \times \left(- 6\right)\right) > 2 x + 8$

$- 6 x - \left(- 24\right) > 2 x + 8$

$- 6 x + 24 > 2 x + 8$

Subtract $24$ both sides:

$- 6 x + 24 - 24 > 2 x + 8 - 24$
$- 6 x > 2 x - 16$

Subtract $2 x$ both sides:

$- 6 x - 2 x > - 16$
$- 8 x > - 16$

When dividing or multiplying by negative number, the inequality sign changes from $>$ to $<$. This is very important to remember.

$x < \frac{- 16}{-} 8$

$x < 2$

Let $x = 1$
$- 6 \left(- 1 - 4\right) > 2 \left(1\right) + 8$
$- 6 \times \left(- 5\right) > 2 + 8$
$30 > 10$