How do you solve #6^(8x+8)-7=2#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Dec 14, 2016 #x=-0.8467# Explanation: #6^(8x+8)-7=2# #=>6^(8x+8)=2+7=9# or #8x+8=log9/log6# or #8x+8=0.9542/0.7781=1.2263# or #8x=1.2263-8=-6.7737# i.e. #x=-6.7737/8=-0.8467# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1324 views around the world You can reuse this answer Creative Commons License