# How do you solve 6^(3m+2)=1?

Dec 23, 2016

$m = - \frac{2}{3}$

#### Explanation:

x^0 = 1 (when $x \ne 0$)

$\therefore {6}^{0} = 1$

(you could also check this by entering ${\log}_{6} \left(1\right)$ into a calculator, to get $0$.)

this gives the equation $3 m + 2 = 0$.

subtract $2$:

$3 m = - 2$

divide by $3$:

$m = - \frac{2}{3}$