# How do you solve #6-3(x-3)<6(x-4)#?

##### 1 Answer

Nov 5, 2015

13/3<x

#### Explanation:

First you distribute the -3(x-3) to get

6-3x+9

then you distribute the other side to get

6x-24

then set up your inequality again to get

6-3x+9<6x-24

now solve for the x

add the 6 and 9 on the left side to equal 15-3x

this comes out to

15-3x<6x-24

add the 24 to the 15 and add the 3x to the 6x to get

39/9<x

which reduces to

13/3<x