How do you solve # 5x^3-3x^2-20x+12=0 #? Algebra Polynomials and Factoring Zero Product Principle 1 Answer G_Dub Apr 29, 2018 You can factorise by grouping in pairs. See below Explanation: #5x^3-3x^2-20x+12=0# #x^2(5x-3)-4(5x-3)=0# #(x^2-4)(5x-3)=0# #(x+2)(x-2)(5x-3)=0# #x=+-2, 3/5# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 2637 views around the world You can reuse this answer Creative Commons License