How do you solve 5sec(theta)+6=0?

1 Answer
Alan P.
Jun 5, 2015

If 5sec(theta) + 6 = 0
color(white)("XXXX")sec(theta) = -6/5
and
color(white)("XXXX")cos(theta) = -5/6

theta = arccos(cos(theta))

rArrcolor(white)("XXXX")theta =arccos(-5/6)

Using my trusty calculator:
color(white)("XXXX")theta = 2.556 " radians"

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