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How do you solve #5e^(3t) = 8e^(2t)#?

1 Answer

Jun 14, 2016

# t = log_e(8/5)#

Explanation:

After some trasformations we get at

#e^{3t}/(e^{2t}) = 8/5# or #e^t = 8/5#

Solving for #t# we have

#t log_e e = t xx 1 = t = log_e(8/5)#

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