How do you solve #5^(x-6)=18#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Sep 16, 2016 #x=7.7959# Explanation: Taking logarithm for #5^(x-6)=18#, we get #(x-6)log5=log18# or #(x-6)xx0.6990=1.2553# or #x-6=1.2553/0.6990=1.7959# or #x=7.7959# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1693 views around the world You can reuse this answer Creative Commons License