How do you solve #5-3c<=c+17#?

1 Answer
Jim G.
Dec 19, 2016

#c>= -3#

Explanation:

Collect terms in c on one side of the inequality and numeric values on the other side.

add 3c to both sides.

#5cancel(-3c)cancel(+3c)<=c+3c+17#

#rArr5<=4c+17#

subtract 17 from both sides.

#5-17<=4c cancel(+17)cancel(-17)#

#rArr-12<=4c#

divide both sides by 4

#(-12)/4<=(cancel(4) c)/cancel(4)#

#rArr-3<=c" or " c>=-3#

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