How do you solve #(-5)^(2x)=625#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Alan N. Aug 27, 2016 #x=2# Explanation: #(-5)^(2x) = 625# #((-5)^2)^x = 5^4# #(5^2)^x = 5^4# #5^(2x) = 5^4# Equating indices #-> 2x=4# #:. x=2# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 4376 views around the world You can reuse this answer Creative Commons License