How do you solve #5-2x>27 #?

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Answer 1 · 2017-01-18T20:23:09

See the entire solution process below:

First, subtract #color(red)(5)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#5 - color(red)(5) - 2x > 27 - color(red)(5)#

#0 - 2x > 22#

#-2x > 22#

Now, divide each side of the inequality by #color(blue)(-2)# to solve for #x# while keeping the inequality balanced.

However, when dealing with inequalities and multiplying or dividing by a negative term we must also reverse the inequality sign:

#(-2x)/color(blue)(-2) color(red)(<) 22/color(blue)(-2)#

#(color(blue)(cancel(color(black)(-2)))x)/cancel(color(blue)(-2)) color(red)(<) -11#

#x < -11#