How do you solve $5-2x>27$ ?

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Answer 1 · 2017-01-18T20:23:09

See the entire solution process below:

First, subtract $color(red)(5)$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$5 - color(red)(5) - 2x > 27 - color(red)(5)$

$0 - 2x > 22$

$-2x > 22$

Now, divide each side of the inequality by $color(blue)(-2)$ to solve for $x$ while keeping the inequality balanced.

However, when dealing with inequalities and multiplying or dividing by a negative term we must also reverse the inequality sign:

$(-2x)/color(blue)(-2) color(red)(<) 22/color(blue)(-2)$

$(color(blue)(cancel(color(black)(-2)))x)/cancel(color(blue)(-2)) color(red)(<) -11$

$x < -11$

How do you solve 5-2x>27 5-2x>27 ?