How do you solve #4x(x+2)=16x-3# by factoring? Algebra Polynomials and Factoring Zero Product Principle 1 Answer sankarankalyanam Mar 20, 2018 #color(green)(x = 3/2, 1/2# Explanation: #4x (x + 2) = 16x - 3# #4x^2 + 8x = 16x - 3, "Removing bracket in L H S"# #4x^2 + 8x - 16x + 3 = 0, "bringing all terms to L H S"# #4x^2 - 8x + 3 = 0# $4x^2 - 2x - 6x + 3 = 0# #2x (2x - 1) - 3 (2x - 1) = 0# (2x -3) * (2x - 1) = 0# #color(green)(x = 3/2, 1/2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 1489 views around the world You can reuse this answer Creative Commons License