How do you solve #4x+5 < 9 #?

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Answer 1 · 2018-03-03T20:51:56

See a solution process below:

First, subtract #color(red)(5)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#4x + 5 - color(red)(5) < 9 - color(red)(5)#

#4x + 0 < 4#

#4x < 4#

Now, divide each side of the inequality by #color(red)(4)# to solve for #x# while keeping the inequality balanced:

#(4x)/color(red)(4) < 4/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) < 1#

#x < 1#