How do you solve $4 x + 3 < 55$ $4x + 3 <55$ ?

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How do you solve $4 x + 3 < 55$ $4x + 3 <55$ ?

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Answer 1 · 2016-06-29T13:55:05

$x < 13$ $x<13$

Explanation:

$General comment$ $color(blue)("General comment")$
Treat like a normal equation. The only thing to watch for is if you multiply an inequality by $(- 1)$ $(-1)$ . This turns the sign round the other way. You do not have any need for multiplying by -1 in this question so it is not an issue.
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$Answering your question$ $color(blue)("Answering your question")$

Given: $4 x + 3 < 55$ $" "4x+3<55$

Subtract 3 from both sides

$4 x < 52$ $4x<52$

Divide both sides by 4

$\frac{4}{4} \times x < \frac{52}{4}$ $4/4xx x<52/4$

But $\frac{4}{4} = 1 and \frac{52}{4} = 13$ $4/4=1" and "52/4=13$

$1 \times x < 13$ $1xx x<13$

$x < 13$ $x<13$

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How do you solve $4 x + 3 < 55$ $4x + 3 <55$ ?

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