How do you solve $4x^(2/3)-6=10$ ?

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Answer 1 · 2016-02-28T13:48:32

$x=(5^(3/2))/(2^(3/2)$

$color(blue)(4x^(2/3)-6=10$

$rarrx^(2/3)=10/4$

$rarrx^(2/3)=5/2$

Take root $2/3$ both sides

$rarrx=root(2/3)(5/2)$

Invert and multiply

$rarrx=(5/2)^(3/2)$

Remember that $(a/b)^x=a^x/b^x$

So

$rArrcolor(green)(x=(5^(3/2))/(2^(3/2))~~39.25...$

Answer 2 · 2016-02-28T13:52:52

$x= +-8$

$4x^(2/3)-6=10$

$rarr 4x^(2/3) = 16$

$rarr x^(2/3)=4$

$rarr x^(1/3) = +-2$

$rarr x= (+-2)^3 = +-8$

How do you solve 4x^(2/3)-6=104x^(2/3)-6=10?