How do you solve #4x^2 - 16 = 0# by factoring?

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Answer 1 · 2015-09-29T12:38:37

#color(blue)(x=+-2#

#4x^2−16=0#

#4x^2−4^2=0#

Here #4# is common to both terms

#4x^2−4^2=4(x^2-4)#

#4(x^2-4)=0#

#x^2-4=0#

#x^2=4#

#x=sqrt4#

#color(blue)(x=+-2#