How do you solve 4(y-1)=3(2+y)4(y−1)=3(2+y)?

1 Answer
Alan P.
Jan 5, 2016

y=10y=10
(see below for solution method)

Explanation:

Given
color(white)("XXX")4(y-1)=3(2+y)XXX4(y−1)=3(2+y)

Expanding both sides:
color(white)("XXX")4y-4=6+3yXXX4y−4=6+3y

Subtract (3y-4)(3y−4) from both sides to isolate the variable on one side and the constant on the other
color(white)("XXX")(4y-4)-(3y-4) = (6+3y)-(3y-4)XXX(4y−4)−(3y−4)=(6+3y)−(3y−4)

Simplify
color(white)("XXX")y = 10XXXy=10

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