How do you solve $3 p + 4 p + 37 = 79$ $3p + 4p + 37 = 79$ ?

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Answer 1 · 2018-03-19T00:33:42

$p = 6$ $p=6$

Let's combine the terms on the left to get:

$7 p + 37 = 79$ $7p+37=79$

We can subtract $37$ $37$ from both sides to get:

$7 p = 42$ $7p=42$

Finally, we can divide both sides by $7$ $7$ to get:

$p = 6$ $p=6$

Answer 2 · 2018-03-19T00:36:43

First add like terms...

$3 p + 4 p + 37 = 79$ $3p+4p+37=79$

$7 p + 37 = 79$ $7p+37=79$

Next subtract 37 from both sides.

$(7 p + 37) - 37 = 79 - 37$ $(7p+37)-37=79-37$

$7 p = 42$ $7p=42$

Divide both sides by seven...

$\frac{7 p}{7} = \frac{42}{7}$ $(7p)/7=42/7$

$p = 6$ $p=6$

How do you solve 3p+4p+37=793p + 4p + 37 = 79?