How do you solve #(4+(-10)-:2)/(7-8)^2#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Jatin Trivedi · EZ as pi Mar 18, 2018 Answer is #-1# Explanation: First simplify the brackets and then apply #BODMAS# #(4-10÷2)/(-1)^2# #(4-5)/1# #4-5# #-1# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1448 views around the world You can reuse this answer Creative Commons License