How do you solve $(3y-4)/0.2-8>12$ and graph the solution on a number line?

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Answer 1 · 2018-05-19T03:32:50

$y>8/3$

$(3y -4)/(0.2) - 8 > 12$

$(3y -4)/(0.2) - 8 + 8 > 12 + 8$

$(3y -4)/(0.2) > 20$

$(0.2)*(3y -4)/(0.2) > 20 *0.2$

$3y -4 > 4$

$3y -4 + 4> 4 + 4$

$3y > 8$

$(3y)/3 > 8/3$

$y > 8/3$

graph{y>8/3 [-10.165, 9.835, -0.48, 9.52]}

How do you solve (3y-4)/0.2-8>12(3y-4)/0.2-8>12 and graph the solution on a number line?