How do you solve #(3y-4)/0.2-8>12# and graph the solution on a number line?

Question

2997 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-19T03:32:50

#y>8/3#

#(3y -4)/(0.2) - 8 > 12#

#(3y -4)/(0.2) - 8 + 8 > 12 + 8#

#(3y -4)/(0.2) > 20#

#(0.2)*(3y -4)/(0.2) > 20 *0.2#

#3y -4 > 4#

#3y -4 + 4> 4 + 4#

#3y > 8#

#(3y)/3 > 8/3#

#y > 8/3#

graph{y>8/3 [-10.165, 9.835, -0.48, 9.52]}