How do you solve $(3x-5.7)/6 = 4.1$ ?

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Answer 1 · 2016-11-04T16:39:13

$x = 10.7$

You need to isolate $x$ which is in the numerator.
Get rid of the denominator first: $xx 6$ on both sides

$color(blue)(cancel6xx)((3x-5.7))/cancel6 = 4.1color(blue)(xx6)$

$3x-5.7 = 26.4" "larr$ add 5.7 to both sides

$3x-5.7color(red)(+5.7) = 26.4color(red)(+5.7)$

$3x = 32.1" "larr div 3$ on both sides

$(3x)/3 = 32.1/3$

$x = 10.7$

How do you solve (3x-5.7)/6 = 4.1(3x-5.7)/6 = 4.1?