How do you solve #3x-3<=6 #?

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Answer 1 · 2018-03-13T12:18:09

See a solution process below:

First, add #color(red)(3)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#3x - 3 + color(red)(3) <= 6 + color(red)(3)#

#3x - 0 <= 9#

#3x <= 9#

Now, divide each side of the inequality by #color(red)(3)# to solve for #x# while keeping the inequality balanced:

#(3x)/color(red)(3) <= 9/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) <= 3#

#x <= 3#