How do you solve $3x^2 − 6 = 4x$ using the quadratic formula?

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Answer 1 · 2016-05-06T20:40:52

When you are solving a quadratic equation, make it equal to 0.
$x = (4+sqrt88)/6$ or $x= (4-sqrt88)/6$

$3x^2 - 4x - 6 = 0$ $" "$ $rArr a = 3, b = -4, c = -6$

$x = [-b +-sqrt(b^2 - 4ac)]/(2a)$

$x = [-(-4) +-sqrt((-4)^2 - 4(3)(-6))]/(2(3))$

$x = [4 +-sqrt(16 + 72)]/(6)$

$x = (4+sqrt88)/6$ or $x= (4-sqrt88)/6$

How do you solve 3x^2 − 6 = 4x 3x^2 − 6 = 4x using the quadratic formula?