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How do you solve # 3x^2 − 6 = 4x# using the quadratic formula?

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1 Answer

May 6, 2016

When you are solving a quadratic equation, make it equal to 0.
#x = (4+sqrt88)/6# or #x= (4-sqrt88)/6#

Explanation:

#3x^2 - 4x - 6 = 0# #" "# #rArr a = 3, b = -4, c = -6#

#x = [-b +-sqrt(b^2 - 4ac)]/(2a)#

#x = [-(-4) +-sqrt((-4)^2 - 4(3)(-6))]/(2(3))#

#x = [4 +-sqrt(16 + 72)]/(6)#

#x = (4+sqrt88)/6# or #x= (4-sqrt88)/6#

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