How do you solve $_^3sqrt(5z-4) + 7 = 10$ ?

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Answer 1 · 2015-04-14T00:59:06

$root(3)(5x-4)+7 = 10$

isolate the cube root
$root(3)(5z-4) = 3$

cube both sides
$5z-4 = 27$

isolate the $z$ term
$5z = 31$

$rarr z = (31)/(5)$

How do you solve _^3sqrt(5z-4) + 7 = 10_^3sqrt(5z-4) + 7 = 10?