How do you solve #3e^(-b)=56#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Sep 21, 2016 #b=-2.9268# Explanation: As #3e^(-b)=56#, we have #3/e^b=56# or #3=56e^b# or #e^b=3/56# and taking natural logarithm on both sides #b=ln3-ln56=1.0986-4.0254=-2.9268# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1659 views around the world You can reuse this answer Creative Commons License