How do you solve $36 x^{2} - 25 = 0$ $36x^2 - 25 = 0$ ?

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Answer 1 · 2016-06-19T11:06:45

$x = - \frac{5}{6} or x = \frac{5}{6}$ $x = -5/6 or x = 5/6$

For quadratic equations, there are 3 methods of solving them:

This equation can be factorised as the difference of two squares.

$36 x^{2} - 25 = 0$ $36x^2 - 25 =0$
$(6 x + 5) (6 x - 5) = 0$ $(6x + 5)(6x - 5)=0$

Let each factor in turn be equal to 0.

If $6x + 5 = 0, " or " if 6x - 5 = 0$
$6x = -5 " " 6x = 5$
$x = -5/6 " " x = 5/6$

There are two solutions as we expect for a quadratic.

How do you solve 36x^2 - 25 = 036x2−25=036x^2 - 25 = 0?