How do you solve #36x^2 - 25 = 0#?

1 Answer
EZ as pi
Jun 19, 2016

#x = -5/6 or x = 5/6#

Explanation:

For quadratic equations, there are 3 methods of solving them:

This equation can be factorised as the difference of two squares.

#36x^2 - 25 =0#
#(6x + 5)(6x - 5)=0#

Let each factor in turn be equal to 0.

If #6x + 5 = 0, " or " if 6x - 5 = 0#
#6x = -5 " " 6x = 5#
#x = -5/6 " " x = 5/6#

There are two solutions as we expect for a quadratic.

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