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How do you solve $- 3 {(x + 2)}^{2} = - 18$ $-3(x+2)^2=-18$ ?

1 Answer

Aug 1, 2016

$x = - 2 \pm \sqrt{6}$ $color(green)(x=-2+-sqrt(6))$

Explanation:

Given
$XXX - 3 {(x + 2)}^{2} = - 18$ $color(white)("XXX")-3(x+2)^2=-18$

Dividing both sides by $(- 3)$ $(-3)$
$XXX {(x + 2)}^{2} = 6$ $color(white)("XXX")(x+2)^2=6$

Taking the roots:
$XXX x + 2 = \pm \sqrt{6}$ $color(white)("XXX")x+2=+-sqrt(6)$

Subtracting $2$ $2$ from both sides
$XXX x = - 2 \pm \sqrt{6}$ $color(white)("XXX")x=-2+-sqrt(6)$

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