# How do you solve  3( x + 1) + 2( x + 2) > 0?

May 5, 2018

$x > - \frac{7}{5}$

#### Explanation:

$3 \left(x + 1\right) + 2 \left(x + 2\right) > 0$

$3 x + 3 + 2 x + 4 > 0$

$5 x + 7 > 0$

$5 x > - 7$

$x > - \frac{7}{5}$

What the answer means is that this equation is only true for any x value that is greater than $- \frac{7}{5}$ ie x values such as $- 1 , - 0.25 , 1 , 3 , 6 , 900$ will satisfy the equation