How do you solve $3 - 6 n - 4 < 17$ $3-6n-4<17$ ?

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How do you solve $3 - 6 n - 4 < 17$ $3-6n-4<17$ ?

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Answer 1 · 2018-07-21T21:32:23

$n > - 3$ $n > -3$

Explanation:

$3 - 6 n - 4 < 17$ $3-6n-4 < 17$

Simplify the left hand side:
$- 1 - 6 n < 17$ $-1 - 6n < 17$

Add $6 n$ $color(blue)(6n)$ to both sides of the inequality:
$-1 - 6n quadcolor(blue)(+quad6n) < 17 quadcolor(blue)(+quad6n)$

#-1 < 17 + 6n

Subtract $color(blue)17$ from both sides:
$-1 quadcolor(blue)(-quad17) < 17 + 6n quadcolor(blue)(-quad17)$

$-18 < 6n$

Divide both sides by $color(blue)6$ :
$(-18)/color(blue)6 < (6n)/color(blue)6$

$-3 < n$

$n > -3$

This can be said as " $n$ is greater than $-3$ ."
enter image source here
(mathwarehouse.com)

The open circle on the $-3$ means that $-3$ is not a solution (but anything greater than it).

Hope this helps!

Answer 2 · 2018-07-21T23:38:50

$n> -3$

Explanation:

We can simplify left side to $-1-6n$ . We now have

$-1-6n<17$

Next, we can add $1$ to both sides to get

$-6n<18$

Lastly, divide both sides by $6$ to isolate $n$ . Recall that since we divided by a negative, the sign flips. We're left with

$n> -3$

Hope this helps!

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How do you solve $3 - 6 n - 4 < 17$ $3-6n-4<17$ ?

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