How do you solve #3*6^(9r)=92.3#?

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Answer 1 · 2016-09-25T01:58:56

#r=0.21249#

#3*6^(9r)=92.3#

divide both sides by 3:
#=>6^(9r)=92.3/3#
#=> 6^(9r)=30.77#

take the log of both sides:
#=> log6^(9r)=log30.77#
#=>9rlog6=log30.77#

divide both sides by #log6#
#=> 9rcancel log6/cancellog6=log30.77/log6#

#=>9r=1.91239# (use calculator)

divide both sides by 9
#=> (cancel9r)/cancel9=1.91239/9=0.21249#

Hence, #r=0.21249#