How do you solve # (3/5)x ≤ 10 + (1/5)x#? Algebra Linear Inequalities and Absolute Value Multi-Step Inequalities 1 Answer Meave60 May 5, 2015 The answer is #x<=25# . Solve #3/5x<=10+1/5x# as if there was an equal sign between the two sides instead of an inequality. Subtract #1/5x# from both sides to get #x# on one side. #2/5x<=10# Multiply both sides by #5/2# to cancel #2/5#. (This is the same as dividing by #2/5# .) #cancel 2/cancel 5x*cancel5/cancel 2<=10*5/2# = #x<=50/2# = #x<=25# Answer link Related questions How do you solve multi step inequalities? What is the difference between solving multi step equations and multi step inequalities? How do you solve multi step inequalities with variables on both sides? How do you solve for x given #x-5>x+6 #? What do you do when your variable cancels out? How do you solve for x when you have #4x-2(3x-9) \le -4(2x-9)#? How do you graph #\frac{5x-1}{4} > -2 (x+5)#? How do you solve for x in #4-6x \le 2(2x+3)#? How do you solve -3x+4<-8#? Which of these values of x satisfies the inequality #-7x+6≤ -8#? See all questions in Multi-Step Inequalities Impact of this question 1283 views around the world You can reuse this answer Creative Commons License