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How do you solve #3^(2a)=3^(-a)#?

1 Answer

Shwetank Mauria

Nov 2, 2016

#a=0#

Explanation:

#3^(2a)=3^(-a)=1/3^a#

i.e. #3^(2a)xx3^a=1=3^0#

or #3^(2a+a)=3^0#

Hence, #3a=0# and #a=0/3=0#

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