# How do you solve 3^(2a)=3^(-a)?

Nov 2, 2016

$a = 0$

#### Explanation:

${3}^{2 a} = {3}^{- a} = \frac{1}{3} ^ a$

i.e. ${3}^{2 a} \times {3}^{a} = 1 = {3}^{0}$

or ${3}^{2 a + a} = {3}^{0}$

Hence, $3 a = 0$ and $a = \frac{0}{3} = 0$