How do you solve #3(1+x)=2[3(x+2)-(x+1)]#?

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Answer 1 · 2016-07-16T16:37:16

#x=-7#

Start by removing the brackets - in the term on the right, start inside the square brackets first.

#3(1+x)=2[3(x+2)-(x+1)]#

#3 + 3x= 2[3x+6 -x-1]#

#3+3x = 2(2x+5)#

#3 +3x = 4x +10#

#3-10 = 4x-3x#

#-7 = x#