How do you solve #2x+7≥-3#?

Question

4604 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-03T16:10:24

See a solution process below:

First, subtract #color(red)(7)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#2x + 7 - color(red)(7) >= -3 - color(red)(7)#

#2x + 0 >= -10#

#2x >= -10#

Now, divide each side of the inequality by #color(red)(2)# to solve for #x# while keeping the inequality balanced:

#(2x)/color(red)(2) >= -10/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) >= -5#

#x >= -5#